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+1 vote
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Two carnot energies A and B are operated in series. Engine A receives heat from a reservoir at 600k and rejects heat to a reservoir at temperature T.

1 Answer

+1 vote
by (79.0k points)
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Best answer

As we know that 

Efficiency of a carnot cycle -

by (248 points)
N=W/Q1-Q2 not
N=W/Q1 only
by (248 points)
Because efficiency is output work divided by the heat given

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