Correct option: (B) 2
Explanation:
First collision will occur when θ satisfies equation
{(θ × r) / v} = [{(2π – θ)r} / {2v}]
i.e. θ = π – (θ/2)
(3/2)θ = π
θ = 120°
After first collision at B m2 will move back with speed V and make second collision with m1 at C.
After second collision at C m1 will move back with speed V and meet m2 at A.
if the third collision at A is neglected then 2 collisions are made before they reach A.
way 2:
Let particle m1 is moving in anticlockwise direction and m2 in clockwise direction. Given is
{(Vm1) / (Vm2)} = (V / 2V) = (1/2)
hence ratio of distance covered will be 2:1 means they collide at B and C.
After these two collision particles will meet again at point A.