Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Surface Areas And Volumes by (15 points)
edited by

The cost of painting the total outer surface of a closed cylindrical oil tank at 60 paise per sq. \( cm \) is Rs. \( 237.60 \). The height of the tank is 6 times the radius of the base of the tank. Find the height and the radius of the tank.

Please log in or register to answer this question.

1 Answer

0 votes
by (53.3k points)

\(h = 6r\)

\(\therefore TSA = 2\pi rh + 2\pi r^2\)

\(= 12\pi r^2 + 2\pi r^2\)

\(= 14\pi r^2\)

\(= 14 \times \frac {22}7 \times r^2 = 44r^2\)

\(\because \) Cost of painting on 1cm2 = 60 paise = ₹0.60

\(\therefore \) Cost of painting on 44r2 cm2 = ₹0.60 x 44 r2

But given that cost of painting of closed cylindrical tank = Rs 237.6

\(\therefore 44 r^2 \times 0.6 = 237.6\)

⇒ \(44r^2 = \frac{237.6}{0.6}\)

⇒ \(r^2 = \frac {237.6}{0.6} \times \frac1{44} = \frac{2376}6 \times \frac1{44} = 9\)

\(\therefore r = 3 cm\)

\(h = 6r = 18 cm\).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...