Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
265 views
in Kinematics by (90 points)
edited by

Find the magnitude and angle with +x-axis of a vector -i + j.

image

Please log in or register to answer this question.

1 Answer

0 votes
by (53.3k points)

Given vector = \(-\hat i + \hat j\)

Magnitude will be = \(\sqrt{1 + 1}\) = \(\sqrt 2\)

Angle 

\(cos \theta = \frac {i.(-\hat i + \hat j)}{|i||-i + j|}\)

\(= \frac{-1}{1 \times \sqrt 2}\)

\(cos \theta = \frac {-1}{\sqrt 2}\)

\(cos \theta = cos 135° \)

\(\theta = 135° \)

Related questions

0 votes
0 answers
0 votes
0 answers
0 votes
0 answers
0 votes
0 answers

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...