Correct option: (A) a – R, b – P, c – Q
Explanation:
Given : F = kx
workdone = w = x(2)∫x(1) F ∙ dx
w = x(2)∫x(1) k × dx
w = k[x2 / 2]x(2)x(1) = (k/2) [x22 – x12]
(1) from x = – 4 to x = – 2,
w = (k/2) [(– 2)2 – (– 4)2] = (k/2) (– 12) = – 6 k = negative
(2) from x = – 2 to x = – 4
w = (k/2) [(– 4)2 – (–2)2] = 6k = positive
(3) form x = – 2 to x = + 2
w = (k/2) [(2)2 – (– 2)2] = 0