The correct option (b) 1
Explanation:
x2 + y2 = 4 ⇒ c1 = centre (0, 0) and r1 = 2
x2 + y2 – 6x – 8y – 24 = 0 ⇒ c2 = (3, 4) and r2 = √(32 + 42 + 24) = 7
Now r2 – r1 = 7 – 2 = 5
and c1c2 = √(32 + 42) = 5
∴ c1c2 = r2 – r1
∴ Given circle touches internally such that they have one common tangent at point of contact.