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in Matrices & determinants by (40 points)

where \( O \) denotes \( 2 \times 2 \) null matrix is f then surn of dights of th.imageplz help give perfect soln

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M = \(\begin{bmatrix} a & -360 \\ b & c \\ \end{bmatrix}\)

M\(\begin{bmatrix} a & -360 \\ b & c \\ \end{bmatrix}\) \(\begin{bmatrix} a & -360 \\ b & c \\ \end{bmatrix}\)

\(\begin{bmatrix} a^2&-360 b \,\,\,-360(a+c)\\ b(a+c) &\,\, c^2 -360\,b \end{bmatrix}\)

-360 (a+c) = 0 ⇒ a = -c

a2 - 360 b = 0 ⇒ b = \(\frac{a^2}{360}\)

a,b,c are integer

so , for smallest positive value of b , we have 

a = 1 or a = -1

∴ b = 1/360 is smallest positive value of  b where ois null matrix . only

needed condition is c = -a

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