M = \(\begin{bmatrix}
a & -360 \\
b & c \\
\end{bmatrix}\)
M2 = \(\begin{bmatrix} a & -360 \\ b & c \\ \end{bmatrix}\) \(\begin{bmatrix} a & -360 \\ b & c \\ \end{bmatrix}\)
= \(\begin{bmatrix} a^2&-360 b \,\,\,-360(a+c)\\ b(a+c) &\,\, c^2 -360\,b
\end{bmatrix}\)
-360 (a+c) = 0 ⇒ a = -c
a2 - 360 b = 0 ⇒ b = \(\frac{a^2}{360}\)
a,b,c are integer
so , for smallest positive value of b , we have
a = 1 or a = -1
∴ b = 1/360 is smallest positive value of b where o2 is null matrix . only
needed condition is c = -a