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in Physics by (54.5k points)

The separation between a node and the next antinode in a vibrating air column is 25 cm. If the speed of sound in air is 340 m/s, find the frequency of vibration of the air column.

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The separation between a node and the next antinode is equal to one-fourth of the wavelength. Hence from the given data of the problem, 

λ/4 = 25 cm = 0.25 m 

→ λ= 4*0.25 m =1.0 m. 

The speed of sound in air V = 340 m/s. 

Hence the frequency of the vibration ν = V/λ

→ν = 340/1.0 Hz =340 Hz

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