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For reaction Y2 + 2Z → Product, rate controlling step is Y + ½ Z → Q.

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For reaction Y2 + 2Z  → Product, rate controlling step is Y + ½ Z → Q. If the concentration of Z is doubled, the rate of reaction will be

(a)   remain the same

(b)   become four times

(c)   become 1.414 times

(d)   become double 

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Correct option   (c) become 1.414 times

Explanation:

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