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Consider the following reaction.

On estimation of bromine in 1.00 g of R using Carius method, the amount of AgBr formed (in g) is ______.

[Given: Atomic mass of H = 1, C = 12, O = 16, P = 31, Br = 80, Ag = 108].

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Molecular weight of (R) = 7 x 12 + 1 x 6 + 80 x 2= 250 g/mol

Mole of AgBr formed = 2 x mole of (R)

= 2 x 1/250 x 188 

= 8 x 10-3 x 188

= 1.504 g

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