Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
173 views
in Economics by (70.4k points)
closed by

Using the following frequency distribution of marks of students of a school, find range and relative range of the marks:

Marks 20 - 30 30 - 40 40 - 50 50 - 60 60 - 70 70 - 80
No. of students 8 20 25 60 45 10

1 Answer

+1 vote
by (73.6k points)
selected by
 
Best answer

Here, xH = Upper limit of the last class 70 – 80 = 80 marks

xL = Lower limit of the initial class 20 – 30 = 20 marks

Range of marks of students :

R = xH – xL

= 80 – 20 = 60 marks

Relative range of marks:

Relative range = \(\frac{R}{x_H+x_L}\)

\(\frac{60}{80+20}\)

\(\frac{60}{100}\)

= 0.60

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...