Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
375 views
in Economics by (70.4k points)
closed by

The marks obtained by 9 students in a test of 100 marks in Mathematics are given below:

64, 63, 72, 65, 68, 69, 66, 67, 69

Find the standard deviation of marks obtained by the students.

1 Answer

+1 vote
by (73.6k points)
selected by
 
Best answer

Here n = 9

Mean:

x̄ = \(\frac{Σx}{n}=\frac{603}{9}\) = 67 marks

Standard deviation of marks:
s = \(\sqrt\frac{Σ(x−\bar x)^2}{n}\)
\(\sqrt\frac{64}{9}\)
\(\sqrt{7.111}\)
= 2.67 marks

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...