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In how many ways can 4 boys and 3 girls be arranged In a row such that no two boys and no two girls are together?

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4 boys and 3 girls can be arranged in a row in the order B G B G B G B so that no two boys and no two girls are together
∴ Total permutations = 4P4 × 3P3
= 4! × 3!
= 24 × 6
= 144

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