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In how many ways can 4 boys and 4 girls be arranged In a row such that no two boys and no two girls appear together?

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In how many ways can 4 boys and 4 girls be arranged In a row such that no two boys and no two girls appear together?

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4 boys and 4 gIrls can be arranged In a row in the following order of arrangements in which two boys and two girls do not appear together.

Hence, the total number of ways of arranging 4 boys and 4 girls in a row, so that two boys and two girls do not appear together = 576 + 576 = 1152

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