3.(n + 3)p4 = 5.(n + 2)p4
∴ 3.(n + 3) (n + 3 – 1) (n + 3 – 2) (n + 3 – 3) [According to definition of nPr]
= 5.(n + 2) (n + 2 – 1) (n + 2 – 2) (n + 2 – 3) 3.(n + 3) (n + 2) (n + 1) (n)
= 5.(n + 2) (n + 1) (n) (n- 1)
∴ 3(n + 3) = 5(n – 1)
∴ 3n + 9 = 5n – 5
∴ 9 + 5 = 5n – 3n
∴ 14 = 2n
∴ n = 142 = 7