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How many six digit numbers can be formed using all the digits 1, 2, 3, 0, 7, 9?

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Best answer

Using all the digits 1, 2, 3, 0, 7, 9, six digit numbers are to be formed.
∴ Excluding digit 0, one of the five digits can be placed at the first place in 5P1 ways

Now, remaining 5 digits (including 0) can be arranged in remaining 5 places in 5P5 ways.

∴ Total permutations for six digit numbers

5P1 × 5P5

= 5 × 5!

= 5 × 120

= 600

Hence, 600 numbers of 6 digit can be formed.

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