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There are 7 cages for 7 lions in a zoo. 3 cages out of 7 cages are so small that 3 out of 7 lions cannot fit in it. In bow many ways can 7 lions be caged in 7 cages?

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Except 3 small cages In remaining 4 cages 3 lions can be caged In 4P3 ways.

Now, In the remainIng (1 big + 3 small) 4 cages the remainIng 4 lions can be caged In 4P4 ways.

∴ Total permutations of cagIng 7 lions in

7 cages = 4P3 . 4P4

= (4 × 3 × 2) × 4!

= 24 × 24

= 576

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