Question

Using all the digIts 2, 3, 5, 8, 9, how many numbers greater than 50,000 can be formed?

Answer 1

Given digits are 2, 3, 5, 8, 9.

For the numbers greater than 50.000 the digit at the first place may be 5 or greater than It.

∴ Out of the digit 5, 8, 9, the first digit can be placed in ³P₁ ways.

Now, from the remaIning 4 dIgits, all four can be placed in 4P4 ways.

∴ Total permutations for the numbers greater than 50,000 = ³P₁ × ⁴P₄

= 3 × 4!

= 3 × 24

= 72