5 % of items are defective in a box of 200 items.
∴ No. of defective items in the box = 200 × 5 / 100 =10 items.
3 items are selected from the box. Such that all three items are defective.
∴ Total combinations = 10C2
= \(\frac{10×9×8}{3×2×1}\)
= 720 / 6 = 120