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in Laws of motion by (25 points)
edited by

Block \( A \) is moving away from the wall at a speed \( v \) and acceleration \( a \). 

(1) Velocity of \( B \) is \( v \) with respect to \( A \). 

(2) Acceleration of \( B \) is a with respect to \( A \). 

(3) Acceleration of \( B \) is \( 4 a \) with respect to \( A \). 

(4) Acceleration of \( B \) is \( \sqrt{17} a \) with respect to \( A \).

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1 Answer

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by (80.9k points)
edited by

A will be move = x 

B will move = 4x

V= dx/dt = v

VB \(4\frac{dx}{dt}\)

VAB = VB -VD

\(4u\hat{j}-u\hat{i}\)

\(\vec{a}_{BD}=a\hat{i}-4a\hat{j}\)

\(|\vec{a}_{BD}|=\sqrt{(4a)^2 +(1a)^2}\)

\(=\sqrt{17}a\)

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