In a box there are 3 white and 5 pink flowers.
(1) Selected three flowers are of the same colour:
3 whIte flowers of 3 white flowers can be selected in 3C3 ways or
3 pink flowers of 6 pink flowers can be selected in 6C3 ways.
∴ Total combinations = 3C3 + 5C3
= 1 + \(\frac{5×4×3}{3×2×1}\)
= 1 + 10 = 11
(2) Selected two flowers are of different colours:
1 white flowers out of 3 whIte flowers can be selected in 3C1 ways and
1 pink flower out of 5 pink flowers can be selected In 5C1 ways.
∴ Total combinations = 1C1 × 8C3
= 3 × 5
= 15