**In a box there are 3 white and 5 pink flowers.**

**(1) Selected three flowers are of the same colour:**

3 whIte flowers of 3 white flowers can be selected in ^{3}C_{3} ways or

3 pink flowers of 6 pink flowers can be selected in ^{6}C_{3} ways.

∴ Total combinations = ^{3}C_{3} + ^{5}C_{3}

= 1 + \(\frac{5×4×3}{3×2×1}\)

= 1 + 10 = 11

**(2) Selected two flowers are of different colours:**

1 white flowers out of 3 whIte flowers can be selected in ^{3}C_{1} ways and

1 pink flower out of 5 pink flowers can be selected In ^{5}C_{1} ways.

∴ Total combinations = ^{1}C_{1} × ^{8}C_{3}

= 3 × 5

= 15