Out of 8 different books, 5 books are to be selected.
(1) A particular book is always selected : If a particular book is always selected, then out of 7 remaining books, the remaining 4 books can be selected in 7C4 ways.
∴ Total combinations = 1C1 × 7C4
= 1 × \(\frac{7×6×5×4}{4×3×2×1}\)
= 35
(2) A particular book is never selected:
If a particular book is never selected, then out of the remaining 7 books, 5 books can be selected in 7C5 ways.
∴ Total combinations = 7C5
= \(\frac{7×6×5×4\times3 }{4×3×2×1\times1}\)
= 21