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Obtain the expansion of the following binomial expressions:

(3a + 4b)3

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(3a + 4b)3 

3C0 (3a)3 (4b)0 + 3C1 (3a)2 (4b)1 + 3C2 (3a) (4b)2 + 3C3 (3a)0 (4b)3

= 1 . 27a3. 1 + 3 . 9a. 4b + 3 . 3a . 16b2 + 1 . 1 . 64b3

= 27a3 + 108a2b + 144b2 + 64b3

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