The frequency of the sound = 400 Hz The speed of sound in air V = 335 m/s
The speed of car u = 54 km/h = 54000/3600 m/s =15 m/s
(a) The apparent frequency in front of the car v' = Vv/(V-u) =335*400/(335-15) Hz =418.75 Hz
Hence the wavelength = V/v' = 335/418.75 m = 0.80 m
= 80 cm
(b) The same apparent frequency will be reflected by the cliff, hence the wavelength of the reflected frequency will be the same i.e.
= 80 cm
(c) For the person sitting in the car, the apparent frequency reflected by the cliff is the frequency from the stationary source while the observer is moving at a speed of 15 m/s. Hence the frequency heard by him = (V+u)v'/V
= (335+15)418.75/335 Hz
= 350*418.75/335 Hz
≈ 437 Hz
(d) The beat frequency reached the person in the car
= 437 -400 Hz
= 37 Hz
Since the beat frequency is more than 16 Hz which is beyond the normal person's perception, hence the person may not hear any beat.