Given: The difference between two molar specific heat of gas is 8000 J.kg/K and the ratio of two specific heat is 1.65.
Solution:
Let x and y be molar specific heat of two given gases.
The difference between molar specific heat = 8000 J.Kg/K'
∴ x - y = 8000 ........(1) (let x > y)
ratio of specific heat is 1.65
∴ x/y = 1.65
⇒ x = 1.65y .......... (2)
Now, putting Eqn(2) in Eqn(1) we get,
1.65y - y = 8000
⇒ 0.65y = 8000
⇒ y = 8000/0.65 = 12307.6923
And, x = 1.65y ⇒ 1.65*12307.6923
x ⇒20307.692295
Thus,
y≈ 12307.69
x≈ 20307.69