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A compound H2X with molar weight of 80g is dissolved in a solvent having density of 0.4 gml-1. Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is_____

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Here, Vsolution ≈ Vsolvent

Since, in 1l solution , 3.2 moles of solute are present, 

So, 1l solution ≈ 1l solvent (d = 0.4g/ml) ≈ 0.4 kg

So, molality (m) = moles of solute /mass of solvent (kg) = 3.2/0.4 = 8

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