Question

For a G.P., a = 4/9 and r = −3/2. Find T₃.

Answer 1

a = \(\frac{4}{9}\), r = T₃ =?

T = (\(\frac{4}{9}\))\((−\frac{3}{2})^{3−1}\)

= (\(\frac{4}{9}\))\((−\frac{3}{2})^2\)

= \(\frac{4}{9}\) × \(\frac{9}{4}\)

= 1

Hence, the third term of a G.P. is 1.