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If Sn = 4(3^n – 1), find Tn+1.

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If Sn = 4(3n – 1), find Tn+1.

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Sn = 4 (3n – 1)

Now, Tn+1 = Sn+1 – Sn

= 4[3n+1 – 1] – 4[3n – 1]

= 4[3n+1 – 1 – 3n + 1]

= 4[3n(3 – 1)]

= 4(3n × 2)

∴ Tn+1 = 8(3)n

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