Table–1 Table–2 (A) time period of an earth satellite in circular orbit (P) Independent of mass

Question

Match the following

Table–1	Table–2
(A) time period of an earth satellite in circular orbit	(P) Independent of mass of satellite
(B) Orbital velocity of satellite	(Q) independent of radius of orbit
(C) Mechanical energy	(R) independent of mass of earth
	(S) none

Answer 1

A-P,   

B-P,    

C-S

Explanation:

(A) Time period is independent of mass of satellite as

T = 2π(r³ / gR²)^1/2 

(B) Orbital velocity of satellite is independent of mass of satellite (P) as 

V = √(GM / r) where M is mass of planet 

(C) Mechanical energy of satellite = [(– GMm) / (2R)]

hence  A → P 

B → P 

C → S