Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
757 views
in Physics by (76.5k points)

Match the following

Table–1 Table–2
(A) kinetic energy (P) [(– GMm) / (2r)]
(B) Potential energy (Q) √(GM / r)
(C) Total energy (R) – [(GMm) / r]
(D) orbital velocity

(S) [(GMm) / (2r)]

1 Answer

+1 vote
by (66.0k points)
selected by
 
Best answer

A-S,    

B-R,     

C-P,     

D-Q   

Explanation:

(A) kinetic energy = [(GMm) / (2r)]

(B) Potential energy = – [(GMm) / r]

(C) Total energy = [(– GMm) / (2r)]

(D) orbital velocity = √(GM / r)

i.e. A → S 

B → R 

C → P 

D → Q

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...