Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
747 views
in Mathematics by (69.2k points)
edited by

If slope of the tangent at point (x, y) of curve y = f(x) is given by 2y/x2 . If this curve passes through the centre of the circle x2 + y2 – 2x – 2y = 0 then the curve is :

(1)  xln(y) = 2(x-1)

(2)  x2ln(y) = 2(x-1)

(3)  x2ln(y) = (x-1)

(4)  xln(y) = (x-1)

Please log in or register to answer this question.

1 Answer

+1 vote
by (59.7k points)

Correct option  (1)  xln(y) = 2(x-1)

Explanation:

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...