Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
2.1k views
in Mathematics by (73.2k points)

A hyperbola has center at origin and passing through (4, - 2√3) and having directrix 5x = 4√5 then eccentricity of hyperbola (e) satisfy the equation

(1)  4e4 - 24e2 + 35 = 0

(2)  4e4 + 24e2 - 35 = 0

(3)  4e4 - 24e2 - 35 = 0

(4)  4e4 + 24e2 - 35 = 0

Please log in or register to answer this question.

1 Answer

+1 vote
by (69.2k points)
edited by

Correct option  (1)  4e4 - 24e2 + 35 = 0

Explanation:

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...