f(x) = 15x3– 4x2 + x + 10 में x = 2 और 1 रखने पर
f(2) = 15 (2)3 – 4(2)2 + 2 + 10
= 15 × 8 – 4 × 4 + 2 + 10
= 120 – 16 + 2 + 10
= 132 – 16
∴ f(2) = 116
f(1) = 15(1)3 – 4(1) + 1 + 10
= 15 × 1 – 4 + 1 + 10
= 15 – 4 + 1 + 10
= 26 – 4
∴ f(1) = 22
अब\(\frac{ f(2)}{f(1)}=\frac{116}{22}=\frac{58}{11}\)
∴\( \frac{f(2)}{f(1)}\) का मूल्य \(\frac{58}{11}\) होगा ।