Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
115 views
in Statistics by (54.4k points)
closed by

यदि f(x) = 15x3 – 4x2 + x + 10, x ∈ R हो, तो  का मूल्य ज्ञात करो ।

1 Answer

+1 vote
by (55.9k points)
selected by
 
Best answer

f(x) = 15x3– 4x2 + x + 10 में x = 2 और 1 रखने पर

f(2) = 15 (2)3 – 4(2)2 + 2 + 10

= 15 × 8 – 4 × 4 + 2 + 10

= 120 – 16 + 2 + 10

= 132 – 16

∴ f(2) = 116

f(1) = 15(1)3 – 4(1) + 1 + 10

= 15 × 1 – 4 + 1 + 10

= 15 – 4 + 1 + 10

= 26 – 4

∴ f(1) = 22

अब\(\frac{ f(2)}{f(1)}=\frac{116}{22}=\frac{58}{11}\)

\( \frac{f(2)}{f(1)}\) का मूल्य \(\frac{58}{11}\) होगा ।

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...