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यदि f(x) = \(\sqrt{5600−4x}\), x ∈ R है । x = 1000 हो, तो f(x) ज्ञात करो और x की कौन-सी किंमत के लिए f(x) = 20

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f(x) =\(\sqrt{ 5600−4x}\)में x = 1000 रखने पर

∴ f(1000) = \(\sqrt{5600−4(1000)}\)=\(\sqrt{5600−4000}=\sqrt{1600}\)

∴ f(1000) = 40

f(x) = 20 दिया है ।

∴ 20 =\(\sqrt{ 5600−4x}\) (दो और वर्ग करने पर)

∴ 400 = 5600 – 4x

∴ 4x = 5600 – 400

∴ 4x = 5200

∴ x =\(\frac{ 5200}4\)

∴ x = 1300

f(x) = 40 और x = 1300 होगा ।

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