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+1 vote
889 views
in Chemistry by (76.3k points)

Rate constant for a reaction are 2.5 x 10-4 atm and 1 atm at temperature 327°C and 527°C respectively. Calculate activation energy in KJ.

(Given R = 8.314 J mol-1K-1)

(1) 166 KJ

(2) -257 KJ

(3) 120 KJ

(4) 70 KJ

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1 Answer

+1 vote
by (65.8k points)

Correct option: (1) 166 KJ

Explanation: 

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