Question

The period of oscillation of a simple pendulum is given by T = 2π √(ℓ/g) what is the equation of the relative error ΔT/T in measurement of period T ?

 (a) (1/2) (Δℓ / ℓ)  (b) 2(Δℓ / ℓ) (c) (1/4) (Δℓ / ℓ)  (d) 4(Δℓ / ℓ)

Answer 1

(a) (1/2) (Δℓ / ℓ)

Explanation:

T = 2π √(l/g) = 2π(l/g)^1/2

(ΔT / T) = (1/2) (Δℓ / ℓ)