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Equation of a common tangent to the circle, x^2 + y^2 - 6x = 0 and the parabola, y^2 = 4x, is

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Equation of a common tangent to the circle, x2 + y2 - 6x = 0 and the parabola, y2 = 4x, is

(1)   2√3y = 12x + 1

(2)  2√3y = -x - 12

(3)  √3y = 2x + 1

(4)  √3y = x + 3

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1 Answer

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Correct option  (4)  √3y = x + 3

Explanation:

Tangent to y2 = 4x is 1 y mx + 1/m 

 its distance from (3, 0) is equal to '3'

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