Question

The correct order of intensity of compound is

(i) [Ni(CN)₂]^-2

(ii) [Ni(Cl)₄ ]^2-

(iii) [Ni (H₂O)₆]

Answer 1

The geometry of the given complexes as

[Ni(CN)₂]^-2 → square planer

[Ni(Cl)₄]^2- → tetrahedral.

[Ni(H²O)₆] → octahedral.

As we know ,

CN^- is strong filed ligand . than H₂O and the spilling of octahedral and square plane complex are grater than tetrahdral complexes

∴ the order of splitting energy will be -

[Ni(CN)₄]^-2 > [Ni(H₂O)₆] > [Ni Cl₄]^-2

∴ order of there intersities - will be

[NiCl₄]^-2 > [Ni(H₂O)₆] > [Ni (CN)]^-2

(intensities x 1/splitting energy)