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+1 vote
95.7k views
in Mathematics by (44.7k points)

Equation of a common tangent to the parabola y2 = 4x and the hyperbola xy = 2 is : 

(1) x – 2y + 4 = 0 

(2) x + y + 1 = 0 

(3) x + 2y + 4 = 0 

(4) 4x + 2y + 1 = 0

1 Answer

+2 votes
by (69.7k points)
selected by
 
Best answer

The correct option is  (3) x + 2y + 4 = 0.

Explanation:

Let the equation of the tangent to the parabola is y = mx + 1/m it is also tangetn to the hyperbola, so we get 

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