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in Olympiad by (76.5k points)

Let P1(x) = x2 +a1x + b1 and P2(x) = x2 +a2x + b2 be two quadratic polynomials with integer coefficients. Suppose a1 ≠ a2 and there exist integers m ≠ n such that P1(m) = P2(n), P2(m) = P1(n). Prove that a1 – a2 is even.

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P1(x) = x2 +a1x + b1

P2(x) = x2 +a2x + b2         a1,b1,a2,b2 are integers

Now, as m, n are integers so (m + n) is also an integer and 

∴ a1 + a2 must be even integer. It is possible only when both a1 and a2 are even or odd. In both the cases

we get (a1 – a2) always be even.

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