P1(x) = x2 +a1x + b1
P2(x) = x2 +a2x + b2 a1,b1,a2,b2 are integers
Now, as m, n are integers so (m + n) is also an integer and
∴ a1 + a2 must be even integer. It is possible only when both a1 and a2 are even or odd. In both the cases
we get (a1 – a2) always be even.