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in Mathematics by (73.1k points)

If the area of the triangle whose one vertex is at the vertex of the parabola, y2 + 4(x – a2) = 0 and the other two vertices are the points of intersection of the parabola and y-axis is 250 sq. units, then a value of 'a' is :

(1)   5(21/3

(2)   5

(3)    (10)2/3

(4)   5

1 Answer

+1 vote
by (59.6k points)
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Best answer

Correct option  (4)  5

Explanation:

Vertex of the parabola is (a2, 0)

y2 = –4(x – a2)

P.O.I. of parabola and x = 0

=> (0, ±2a)

Area of triangle = 1/2.4a.(a2)  = 250 

 a3 = 125 or a = 5

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