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A battery of 2V and internal resistance 1 is used to send a current through a potentiometer wire of length 200 cm and resistance 4 Q What is the potential gradient of the wire ? 

(A) 8 × 10–3 V cm–1 

(B) 4 × 10–3 V cm–1 

(C) 6 × 10–3 V cm–1 

(D) 2 × 10–3 V cm–1

1 Answer

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Best answer

The correct option is (A) 8 × 10–3 V cm–1.

Explanation:

i = [(EMF of battery) / (r + R)] = [2 / (1 + 4)] = (2/5)A = 0.4A 

Potential difference across wire = 0.4 × 4 = 1.6V 

Potential gradient = [(Potential difference across the wire) / (length of wire)] 

= [(1.6V) / (200cm)] = 8 × 10–3 V/cm

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