Question

The current taken from 30V supply and the current through the 6Ω resistor are respectively.

(A) 6A, 2A 

(B) 6A, (5/6)A 

(C) 5A, (5/3)A 

(D) 5A, (5/6)A

Answer 1

The correct option is (C) 5A, (5/3)A.

Explanation:

The circuit can be reduced as

∴ R_Total = 2 + 2 + (3 || 6) = 4 + [(3 × 6) / (3 + 6)] = 4 + 2 = 6Ω 

∴ I from 30V battery = (30 / 6) = 5A 

Current through 6Ω is I' and 

I' = I × [3 / (3 + 6)] = 5 × (3/9) = (15 / 9) = (5/3)A