The correct option is (A) 10°C.
Explanation:
Let the temperature of mixture = T
∴ heat absorbed by ice = heat lost by water
∴ heat required to melt ice + heat to reach T = heat lost by water.
∴ mL + mC(T – O) = mC(100 – T)
Given L = Latent heat of ice = 80 Cal/g C = 1 Cal/9°C
∴ (100 × 80) + (100 × 1)T = 100 × 1(100 – T)
∴ 8000 + 100T = 10000 – 100T
∴ 200T = 2000 T = 10°C