Let a, b, c > 4
=> One of a, b, c must be 4
Let a = 4
4 × 4 × bc = (7) (3 + b) (3 + c)
16 × bc = 7 (3 + b) (3 + c)
One of b, c must be 7 let b = 7
16 × 7 × c = 7 × 10 × (3 + c)
=> c = 5
Possible (a, b, c) = (4, 7, 5) and its arrange also it is unique
∴ a + b + c = 16