Question

The equation of circle which passes through the origin and cuts off intercepts 5 and 6 from the positive parts of the axes respectively, is

(a) (x+5/2)² +(y+3)² = \(\frac{61}{4}\)

(b) (x–5/2)² +(y–3)² = \(\frac{61}{4}\)

(c) (x–5/2)² –(y–3)² = \(\frac{61}{4}\)

(d) (x–5/2)² +(y+3)² = \(\frac{61}{4}\)

Answer 1

Correct option is  (b) (x–5/2)² +(y–3)² = \(\frac{61}{4}\)