(2) 9.2x10-8 (new energy unit) (mole-1) (0F)-1
We first note that the 1 mole would still contain the same number of ‘entities’.
Also 1J = 1 kg (1m)2 (1s)-2
=(1kg/2kg) (1m/5m)2 (1s/1ms)-2 new energy units
= 2 x 10-8 new energy units
Also 100 divisions on the celsius scale = 100 divisions on the kelvin scale = 180 divisions on the Fahrenheit scale.
∴ 1K = 1.8°F
(1K)-1 = (1.8)-1 (0F)-1
∴ R = 8.32 J (mole-1) (K)-1
= 8.32 (2x10-8 new energy units) (mole-1) [(1.8)-1(°F)-1]
= 16.64/1.8 x 10-8 (new energy unit) (mole)-1(°F)-1
= 9.23 x 10-8 (new energy unit) (mole)-1(°F)-1
= (9.2 x 10-8) (new energy unit) (mole)-1(°F)-1