(4) (1)
We have,
[h] (= energy x time) = [ML2T-1]
[G] = (Force x distance2/mass2) = [M-1L3T-2]
[C] = (Velocity) = [LT-1]
∴ From the given relation, we get
[M2] = [ML2T-1]a [LT-1] [M-1L3T-2]-1
These give,
a+1 = 2; 2a+1–3 = 0; -a -1+2 = 0
The value of, a, consistent with all these relations, is a = +1