Calculate the force (F) required to cause the block of mass m1= 20 kg just to slide under the block of mass m2= 10 kg [u=0.25 for all surfaces]

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AnjaliJangir · Answer 1 · 2023-01-23T12:06:28+0000

$Tcos52° + N = mg$

$\frac N$ = T cos52° $

$\frac N4 + N = 200$

$\frac {5N}4 = 200$

$N = 1600N$

$f_1 = \frac N4$

$= \frac{1600}4$

$= f_1 = 40 N$

$N_1 + Tcos52° = 300$

$N_1 = 260 N$

$f_2 = \frac{N_1}4 $

⇒ $65N$

$F = f_1 + f_2$

$F = 40 + 65$

$F = 10 5N$