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When a1/a2 = b1/b2 ≠ c1/c2 then the system of equation a1x + b1y + c1 = 0.

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When  a1/a2  =  b1/b2  ≠ c1/c2   then the system of equation a1x + b1y + c1 = 0. and a2x + b2y + c2 = 0. 

(A)  has two solutions

(B)  has no solutions

(C)  has infinitely many solutions

(D)  has unique solution

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1 Answer

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Best answer

Correct option  (B) has no solutions

Explanation :

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

then  a1/a2  =  b1/b2  ≠ c1/c2 shows equation has no solution.

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